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if P(-1,0), Q(0,0), R(3,3^(1/2)) are three points then the equation of angle bisector of PQR is
Slope = tan(theta) b/w the lines PQ and PR would be:m = tan(theta) = |m1 – m2|/|1 + m1*m2|where m1 = 0m2 = (root(3) – 0)/4 = > root(3)/4Put m1 and m2 values in m to get thetha angle or slope.thus,m = tan(theta) = root(3)/4theta = arctan(root(3)/4)theta / 2 = [arctan(root(3)/4)]/2=> 23.4/2 degree=> 11.7 degree.new slope for bisector = > tan(11.7) => 0.20 (approx.)Eqn of bisector,=> y = (0.20)x
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