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`        if one root of the quadratic equation ax^2+bx+c=0 is equal to the nth powe of the other root ,then find the value of (ac^n)1/n+1 + (a^n * c)^1/n+1=`
2 years ago

```							Dear student  Sol. Let α, β be the roots of eq. ax2 + bx + c = 0 According to the question, Β = αn Also α + β = -b/a ; αβ = c/a α β = c/a ⇒ α. α n = c/a ⇒ α = (c/a)1/n + 1 then α + β = - b/a ⇒ α + αn = -b/a or (c/a)1/n + 1 + (c/a)n/n + 1 = -b/a ⇒ a .(c/a)1/n + 1 + a .(c/a)n/n + 1 + b = 0 ⇒ an/n + 1 c1/n + 1 + a1/n + 1 c n/n + 1 + b = 0 ⇒ (an c) 1/n + 1 + (can) 1/n + 1 + b = 0  RegardsArun (askIITians forum expert)
```
2 years ago
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