Grade 11Algebra
if one,omega and omega square are the cube root of unity the the solution of (x-3) the whole square+8=0 is
if one,omega and omega square are the cube root of unity the the solution of (x-3) the whole square+8=0 is
1 Answer
Adarsh
Dear,
(x-3)2= -8
=> x-3=2√2i ( i = √-1 )
=> x= 3+ 2√2i
hope this will help ….
Thanks and Regards
Adarsh
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