if one of the root of the equation 8x square-6x-a-3=0 is the square of the other , then the values of a are (a)- 4,-24 (b)- 4,24 (c)- -4,-24 (d)- -4,24

Question

Charchit Tailong · Answer

root1=p root2=q pq=(-a-3)/8 p+q=6/8 p^2=q

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if one of the root of the equation 8x square-6x-a-3=0 is the square of the other , then the values of a are (a)- 4,-24 (b)- 4,24 (c)- -4,-24 (d)- -4,24

if one of the root of the equation 8x square-6x-a-3=0 is the square of the other , then the values of a are (a)- 4,-24 (b)- 4,24 (c)- -4,-24 (d)- -4,24

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if one of the root of the equation 8x square-6x-a-3=0 is the square of the other , then the values of a are (a)- 4,-24 (b)- 4,24 (c)- -4,-24 (d)- -4,24

if one of the root of the equation 8x square-6x-a-3=0 is the square of the other , then the values of a are (a)- 4,-24 (b)- 4,24 (c)- -4,-24 (d)- -4,24

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