Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
if n=774958p96q and n is divisible by 11, then possible ordered pairs (p,q) are if n=774958p96q and n is divisible by 11, then possible ordered pairs (p,q) are
Dear student For divisibility by 11 (Sum of digits at odd places) - (sum of digits at even places ) should be divisible by 11 (33+q) - (22+p) = 11 +(q-p) should be divisible by 11 Hence p = q Hence (1,1) (2,2)(3,3).....(9,9) can exist
To solve this, you need to know the divisibility rules of 8 and 9 Divisibility rule for 8If the sum of the digits of the number is divisible by 8, then the number is divisible by 8 => 7+7+4+9+5+8+P+9+6+Q is divisible by 8 => 55 + P + Q is divisible by 8 Divisibility rule for 9For a number to be divisible by 9, the last digit should be divisible by 9=> Last digit of the number should be 0 or 9=> Q = 0 or 9Now, if Q = 0=> 55 + P should be divisible by 8=> P = 1 or 9 or 17 or 25=> There are four possible pairs of {P, Q}If Q = 9=> 55 + P + Q should be divisible by 8=>64+ P should be divisble by 8=> P = 0 or 8 or 16=> There are three possible pairs of {P, Q}Total possible pairs of {P, Q} are 4+3 = 7Those pairs are {1, 0} {9, 0} {17, 0} {25, 0} {0, 9} {8,9} {16,9}
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -