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If N= 2^4*3^5*5^2*7^3Then find number of factors of the form 4n+2.Also find number of factors of the form 8n+2

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3 years ago

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137 Points
```							4n+2=2(2n+1), it means u can write N as  2(3^0+3^1+.......+3^5)(5^0+.....+5^2)(7^0+..+7^3)= 1×6×3×4= 72.
```
3 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions