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If m,n are roots of equation x 2 +mn=(m+1)x Then n equals to
Dear Priya sum = m + n now from equation x^2 – (m + 1)x + mn = 0 hence sum = m + 1 = m+ n so n = 1 RegardsArun
x^2-(m+1)x+mn=0so m+n=m+1n=1
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