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If in a series,T n= (n+1)/(n+2)! then ∑ 10 n=0 t n is equal then prove that it is equal to 1-1/12!

If in a series,Tn= (n+1)/(n+2)!  then 10n=0 t is equal then prove that it is equal to 1-1/12! 

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear Nishtha
 
On solving
Tn = 1/(n+2)(n+1)
 Tn = [1/n+1  -  1/n+2]
Now open sigma from n = 0 t0 n = 10
 
Sum = [1/1 - 1/2 ]+[1/2 - 1/3]+[1/3 - 1/4]+......[1/11 - 1/12]
All the terms are cancelled out except 1 and 1/12
 
Sum = 1 - (1/12)
 
 
Regards
Arun (askIITians forum expert)

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