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`        if in a AP, Tn present the nth term, t7:t10=5:7 then the value of t8:t11=?`
9 months ago

Vikas TU
11137 Points
```							Dear student t7 : t10 = 5:7 t7 = a+6d t10 = a+9d a+6d / a+9d = 5/7 7a+42d = 5a+45d 2a =3d a = 1.5d Now t8 = a+7d = 8.5d t11 = a+10d = 11.5d t8/t11 = 8.5/11.5 => 17/23
```
9 months ago
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• NCERT Solutions
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