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Grade: 12th pass
        
if in a AP, Tn present the nth term, t7:t10=5:7 then the value of t8:t11=?
one month ago

Answers : (1)

Vikas TU
8732 Points
							
Dear student 
t7 : t10 = 5:7 
t7 = a+6d 
t10 = a+9d 
a+6d / a+9d = 5/7 
7a+42d = 5a+45d 
2a =3d 
a = 1.5d 
Now 
t8 = a+7d = 8.5d 
t11 = a+10d = 11.5d 
t8/t11 = 8.5/11.5 
=> 17/23 
 
one month ago
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