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`        if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).`
4 years ago

```							∑k2 = [2n3 + 3n2+n]/6  call it eq.(1)∑k = [n2+n]/2 call it eq.(2)∑1 = n call it equation (3)Note all limits are 1 to n.6*eq(1) + 12*eq(2) + 6*eq(3) will give you,∑6*(k2+2k+1)= 2n3+9n2+13n,So, l(k) = 6*(k+1)2,root[l(k)] = root(6) * (k+1).just use equation 2 and 3 to solve for ∑root(l(k))
```
4 years ago
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