if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).

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Akshay · Answer

∑k 2 = [2n 3 + 3n 2 +n]/6 call it eq.(1) ∑k = [n 2 +n]/2 call it eq.(2) ∑1 = n call it equation (3) Note all limits are 1 to n. 6*eq(1) + 12*eq(2) + 6*eq(3) will give you, ∑6*(k 2 +2k+1)= 2n 3 +9n 2 +13n, So, l(k) = 6*(k+1) 2 , root[l(k)] = root(6) * (k+1). just use equation 2 and 3 to solve for ∑root(l(k))

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if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).

if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).

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if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).

if ∑ I(r) =n(2n^2 +9n +13) (limit from r=1 to n) then find sum of ∑ root of I(r).

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