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If f (x) =integral upper limit is x^2 lower limit 1/x^2 vsin( t)dt, then find the value of f (1).

If f (x) =integral
upper limit is x^2
lower limit 1/x^2
vsin( t)dt,
then find the value of f (1).

Grade:Upto college level

1 Answers

bharat bajaj IIT Delhi
askIITians Faculty 122 Points
7 years ago
f(x) = cos t ( upper limit x^2 , lower limit 1/x^2)
f(x) = cos x^2 - cos 1/x^2
f(1) = cos 1 - cos 1 = 0

Reply to this question if i am incorrect.
Thanks & Regards
Bharat Bajaj
askIITians Faculty
IIT Delhi

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