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If f (x) =integral upper limit is x^2 lower limit 1/x^2 vsin( t)dt,then find the value of f (1).

Narasimha Reddy , 11 Years ago
Grade Upto college level
anser 1 Answers
bharat bajaj

Last Activity: 11 Years ago

f(x) = cos t ( upper limit x^2 , lower limit 1/x^2)

f(x) = cos x^2 - cos 1/x^2
f(1) = cos 1 - cos 1 = 0

Reply to this question if i am incorrect.
Thanks & Regards
Bharat Bajaj
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