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If f (x) =integral ofupper limit is x^2 lower limit is 1/x^2sin(v t)dt, then find the value of f (1).

Narasimha Reddy , 11 Years ago
Grade Upto college level
anser 1 Answers
venkatesh vadde

Last Activity: 11 Years ago

integration is (-cos(vt) /v) between limits (-cos(v*x^2)/x^2 +x^2cos(v/x^2) ) f(1)=0

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