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If f (x) =integral of upper limit is x^2 lower limit is 1/x^2 sin(v t)dt, then find the value of f (1).

If f (x) =integral of
upper limit is x^2
lower limit is 1/x^2

sin(v t)dt, then find the value of f (1).

Grade:Upto college level

1 Answers

venkatesh vadde
40 Points
7 years ago
integration is (-cos(vt) /v) between limits (-cos(v*x^2)/x^2 +x^2cos(v/x^2) ) f(1)=0

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