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`        if f(x) and g(x) are 2 polynomials such that h(x)=xf(x3)+xg(x6) is divisible by x2+x+1 then1)f(1)=g(1)2)f(1)=g(1)=0(not equal to zero)3)f(1)=-g(1)4)f(1)=-g(1)=0(not equal to zero)`
3 years ago

```							Roots of x2+x+1 are imaginary that are w and w^2 which are the cubic roots.Hence this would satify the h(w) eqn.Therfore,h(w) = 0 => wf(1) + wg(1) = 0orw(f(1) + g(1)) = 0w cannot be zero hence obviousf(1) + g(1) = 0.Third option
```
3 years ago
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