If f: Q--)Q is defined as f(x)=x^2 (power of x is 2) then F F^-1(9) is equal to A.3B.-3C.{-3,3}

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ankit kumar · Answer

here Function f is not one-one . so inerse of f doesnot exist for given Domain . so answer will be none of these . If we consider domain as +Q or -Q only then answer will be according to them .

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If f: Q--)Q is defined as f(x)=x^2 (power of x is 2) then F F^-1(9) is equal to A.3B.-3C.{-3,3}

If f: Q--)Q is defined as f(x)=x^2 (power of x is 2) then F F^-1(9) is equal to A.3B.-3C.{-3,3}

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If f: Q--)Q is defined as f(x)=x^2 (power of x is 2) then F F^-1(9) is equal to A.3B.-3C.{-3,3}

If f: Q--)Q is defined as f(x)=x^2 (power of x is 2) then F F^-1(9) is equal to A.3B.-3C.{-3,3}

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