To find the value of \( f(1) + f(2) + \ldots + f(25) \) given the recursive definitions of the function \( f \), we first need to compute the values of \( f(n) \) for \( n = 1 \) to \( 25 \). The function is defined as follows:
- \( f(1) = 1 \)
- \( f(2n) = f(n) \)
- \( f(2n + 1) = [f(n)]^2 - 2 \)
Let's calculate \( f(n) \) for \( n = 1 \) to \( 25 \) step by step:
Calculating Values of f(n)
We start with the base case:
Next, we compute \( f(2) \):
Now, for \( f(3) \):
- \( f(3) = [f(1)]^2 - 2 = 1^2 - 2 = -1 \)
Continuing with \( f(4) \):
Next, we find \( f(5) \):
- \( f(5) = [f(2)]^2 - 2 = 1^2 - 2 = -1 \)
For \( f(6) \):
Now, \( f(7) \):
- \( f(7) = [f(3)]^2 - 2 = (-1)^2 - 2 = 1 - 2 = -1 \)
Next, we compute \( f(8) \):
Continuing this process, we find:
- \( f(9) = [f(4)]^2 - 2 = 1^2 - 2 = -1 \)
- \( f(10) = f(5) = -1 \)
- \( f(11) = [f(5)]^2 - 2 = (-1)^2 - 2 = -1 \)
- \( f(12) = f(6) = -1 \)
- \( f(13) = [f(6)]^2 - 2 = (-1)^2 - 2 = -1 \)
- \( f(14) = f(7) = -1 \)
- \( f(15) = [f(7)]^2 - 2 = (-1)^2 - 2 = -1 \)
- \( f(16) = f(8) = 1 \) \
- \( f(17) = [f(8)]^2 - 2 = 1^2 - 2 = -1 \) \
- \( f(18) = f(9) = -1 \) \
- \( f(19) = [f(9)]^2 - 2 = (-1)^2 - 2 = -1 \) \
- \( f(20) = f(10) = -1 \) \
- \( f(21) = [f(10)]^2 - 2 = (-1)^2 - 2 = -1 \) \
- \( f(22) = f(11) = -1 \) \
- \( f(23) = [f(11)]^2 - 2 = (-1)^2 - 2 = -1 \) \
- \( f(24) = f(12) = -1 \) \
- \( f(25) = [f(12)]^2 - 2 = (-1)^2 - 2 = -1 \) \
Summing Up the Values
Now that we have calculated the values of \( f(n) \) from \( n = 1 \) to \( n = 25 \), we can summarize them:
- \( f(1) = 1 \)
- \( f(2) = 1 \)
- \( f(3) = -1 \)
- \( f(4) = 1 \)
- \( f(5) = -1 \)
- \( f(6) = -1 \)
- \( f(7) = -1 \)
- \( f(8) = 1 \)
- \( f(9) = -1 \)
- \( f(10) = -1 \)
- \( f(11) = -1 \)
- \( f(12) = -1 \)
- \( f(13) = -1 \)
- \( f(14) = -1 \)
- \( f(15) = -1 \)
- \( f(16) = 1 \)
- \( f(17) = -1 \)
- \( f(18) = -1 \)
- \( f(19) = -1 \)
- \( f(20) = -1 \)
- \( f(21) = -1 \)