Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If e1=((2^1/3)-1)^1/3 e2=(9^-1/3)-((2/9)^1/3)+((4/9)^1/3) then prove that e1=e2.

If e1=((2^1/3)-1)^1/3 e2=(9^-1/3)-((2/9)^1/3)+((4/9)^1/3) then prove that e1=e2.

Grade:

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
7 years ago
Hello student,
given [e1=(2^{1/3}-1)^{1/3}]
so cubing on both sides we get e13= [(2^{1/3}-1)] ..........(1)
Similarly [e2=(9^{-1/3})(1-2^{1/3}+2^{2/3})]
since [(1-2^{1/3}+2^{2/3})] is in the form of a2-ab+b2=(a3+b3)/(a+b)
where a=2^1/3and b=1
so [e2=3^{1/3}/(2^{1/3}+1)]
also cubing above equation on both sides we get
e23= [3/(3+3*2^{1/3}(2^{1/3}+1))]
= [1/(1+2^{1/3}+2^{2/3})]
as denominator is in the form ofa2+ab+b2=(a3-b3)/(a-b)
e23= [(2^{1/3}-1)/2-1] …...............(2)
so from 1 and 2 we can see that e1=e2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free