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If e1=((2^1/3)-1)^1/3 e2=(9^-1/3)-((2/9)^1/3)+((4/9)^1/3) then prove that e1=e2.
Hello student,given [e1=(2^{1/3}-1)^{1/3}]so cubing on both sides we get e13= [(2^{1/3}-1)] ..........(1)Similarly [e2=(9^{-1/3})(1-2^{1/3}+2^{2/3})]since [(1-2^{1/3}+2^{2/3})] is in the form of a2-ab+b2=(a3+b3)/(a+b)where a=2^1/3and b=1so [e2=3^{1/3}/(2^{1/3}+1)]also cubing above equation on both sides we gete23= [3/(3+3*2^{1/3}(2^{1/3}+1))] = [1/(1+2^{1/3}+2^{2/3})]as denominator is in the form ofa2+ab+b2=(a3-b3)/(a-b)e23= [(2^{1/3}-1)/2-1] …...............(2)so from 1 and 2 we can see that e1=e2
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