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if D(r)=a determinant(which is given in the attached picture). then what is sigma(D(r) where r is from 1 to n

if D(r)=a determinant(which is given in the attached picture). then what is sigma(D(r) where r is from 1 to n

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Grade:11

2 Answers

venkat
105 Points
6 years ago
You just have to apply sigma for one of the column and then expand
Then after simplificaton, the first column elements will be n(n+1), n, 3n.
Now expanding  the deteminant we get ,
=n(n+1)[-8]-n(1-2n)+3n(3+2n)
=-8n2-8n-n+2n2+9n+6n2
=0 is your answer.
Please approve my answer if it helped you.
Digvijay Gadhavi
10 Points
6 years ago
we have to apply sigma along first row and then elements of first row becomes n(n+1),n,n^2 respectively then taking n comman and subtract 3rd coloumn in 1st column and then first coloumn and second coloumn will become same so your answer is 0

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