If both roots of the quadratic equation x 2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are a) -5 b) -4 c) -3 d) -1 (Multiple answers correct) Please explain.

Question

If both roots of the quadratic equation x 2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are ​a) -5 b) -4 c) -3 d) -1 (Multiple answers correct) Please explain.

grenade · Answer

the question is based over location of roots

grenade · Answer

the answer is B C D i will give the prood later

NITISH DESHPANDE · Answer

So what are the correct options?

grenade · Answer

sum of the roots equals 2 (1-k) and this should be grater than 0 secondly prodect of roots k + 5 should be greater than 0 hence there is only one value -5 which could not be substituted approve if useful above too

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If both roots of the quadratic equation x 2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are a) -5 b) -4 c) -3 d) -1 (Multiple answers correct) Please explain.

If both roots of the quadratic equation
x²+ 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are

a) -5
b) -4
c) -3
d) -1

(Multiple answers correct)

Please explain.

4 Answers

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If both roots of the quadratic equation x 2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are ​a) -5 b) -4 c) -3 d) -1 (Multiple answers correct) Please explain.

If both roots of the quadratic equation x2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are ​a) -5b) -4c) -3d) -1 (Multiple answers correct) Please explain.

4 Answers

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If both roots of the quadratic equation x 2 + 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are a) -5 b) -4 c) -3 d) -1 (Multiple answers correct) Please explain.

If both roots of the quadratic equation
x²+ 2 (k-1)x + (k + 5) = 0 are positive then possible integral values of ‘k’ are

a) -5
b) -4
c) -3
d) -1

(Multiple answers correct)

Please explain.