Navjyot Kalra
Last Activity: 10 Years ago
Sol. We know that,
(α – β)2 = [(α + δ) – (β + δ)]2
⇒ (α + β)2 - 4α β = (α + δ + β + δ)2 - 4(α + δ) (β + δ)
⇒ b2/a2 – 4c/a = B2/A2 – 4C/A ⇒ 4ac – b2/a2 = 4AC – B2/A2
[Hence α +β = -b/a, α β = c/a
(α + δ) (β + δ) = - B/A and (α + δ) (β + δ) = C/A]
Hence proved.