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`         If  α , β are roots of the equation 9x2+6x+1=0 then find the equation whose roots are reciprocal to the given roots.`
one year ago

Ass satwik
12 Points
```							f(x)= 9x^2+6x+1 Now we have to find a equation whose root is y where y=(1/x) So x=(1/y)Substituting in f(x) we get f(1/y)= 9(1/y)^2+6(1/y)+1Simplifing will give y^2+6y+9 So, x^2+6x+9=0 is equation with reciprocal roots of 9x^2+6x+1=0.
```
one year ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions