Khimraj
Last Activity: 7 Years ago
= αβ = 6/3 = 2roduct of roots
pα + β = 11/3Then sum of roots = α and β are the roots of the equation 3x2 - 11x + 6 = 0αβ]1/2 = 7/3α-β = [(α+β)2-4
Let another equation is ax2+bx+c=0
other equation has root βα and α-β
Then sum of roots = -b/a = βα +(α-β) = 2 + 7/3 = 13/3
product of roots = c/a = βα*(α-β) = 14/3.
So equation is 3x2-13x+14 = 0.
Hope it clears. If you like answer then please approve it.
