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If An =nCo+nC1+......+nCn Then can i write An= nCo+nC1+......+nCn =2(summation of the half terms of the An) If yes , then plzz explain me about it's middle term Is it will be in pair or not If in pair then with which binomial coefficient? If total number of terms will be odd then obviously middle term will be not in pair.then how can we write the above expression. If it is possible then plzz explain me about it's middle term. Answer me plzzz fully explain it
If n is odd then you can write An= nCo+nC1+......+nCn =2(An= nCo+nC1+......+nC(n-1)/2)but if n is even you cannot write An= nCo+nC1+......+nCn =2(summation of the half terms of the An) but you can write it as An = 2(nCo+nC1+......+nC(n/2 – 1)) + nCn/2 Approve it if it is correct
Dear student Hope your doubt gets cleared Please refer https://www.askiitians.com/iit-study-material/iit-jee-mathematics/algebra/binomial-theorem/
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