If alpha,beta,gamma,delta be the roots of the equation x^4-x^3+2x^2+x+1=0,find the value of 1. (2 alpha + 1)(2 beta + 1)(2 gamma + 1)(2 delta + 1) 2. (alpha square + 1)(beta square + 1) (gamma

Firstly put y=2x+1 and make sab in form of y , by this the coming equation has Root`s (2alpha+1)()()().so the answer of first is 19. Ar second method u should open this and put the values of sum of roots, product of roots taken 2 at a time,taken 3 at a time so the answer comes out to be 19

And similarly u can do the second one put (y=x^2+1) and after that make equation in y and answer comes out to be 4