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If alpha and bita are roots of equation, (x-a)(x-b) +c=0 find the roots of the equation (x-alpha)(x-bita)=c


3 years ago

Ritesh Khatri
76 Points
							(x –  $\alpha$)(x –  $\beta$)=cx2 – ($\alpha$ + $\beta$)x +$\alpha$ $\beta$ = c (eqn 1 ) also (x-a)(x-b) +c=0x2 – (a+b)x +ab + c = 0$\alpha +\beta =a+b$$\alpha\beta = ab + c$now eqn 1 becomes x2 – (a+b)x + ab + c = cx2 – (a+b)x + ab  = 0and roots of this equation are a and b

3 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions