mycroft holmes
Last Activity: 8 Years ago
We have
5/7 = 1/(2!) + 1/3! + 1/(4!)+1/5!+1/6!+5/7!
Hence a1+a2+a3+a4+a5+a6+a7 = 10
This comes from the fact that every rational between 0 and 1 can be uniquely represented with the numbers (1/k!) with k>1 as bases, just like decimal bases.
You can create many such bases e.g. with {1!,2!,3!,....) and the Fibonacci numbers for natural numbers.