AlgebraIf A3B-AC=AA9 the find the A,B&C if each of them is distinctly different digits. RUKHMUDDIN RAJGOLI 7 Years agoGrade
Arun7 Years ago1. [a3b] - [ac] = [aa9] 100a + 30 + b - 10a - c = 100a + 10a + 9 21 + b = 20a + c So clearly we need a=1, and that means c = b+1. There are multiple solutions to this problem. (138 - 19 = 119, 137 - 18 = 119, etc.)