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If a1,a2,.. ....... .are in GP with common ratio r such that (summation of k=1 to n) a(2k-1)=(summation of k=1 to n) a(2k+2)≠0.then possible values of r is.......


2 years ago

							Are you sure that it is not sum k=0 to n (2k+2)?Whatever look at the solution.2k-1=1 for k=1        =3 for k=2        =5 for k=3 and so on2k+2=4 for k=1        =6 for k=2        =8 for k=3 and so on.So r=a2/a1=a3/a2=..=-1 and series sum is equal to -a2.If it helps please approve.

2 years ago
							Now look series sum for infinite go series isS=a1/(1-r)=a1/2 in our case.But we also obtained that S=-a2So a1/2=-a2Or,a2=-a1/2So r=a2/a1=-1/2

2 years ago
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