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```
If a1 a2 a3.... an are in ap with a1= 0 then (a3/a2 + a4/a3 .......an/an-1 ) - a2(1/a2 +1/a3 .... 1/an-2
If a1 a2 a3.... an are in ap with a1= 0 then (a3/a2 + a4/a3 .......an/an-1 ) - a2(1/a2 +1/a3 .... 1/an-2

```
2 months ago

Deevena
15 Points
```							a/1-b=b/1-c=c/1-c=ka=k-kcC=k-k^2+k^2(k-k c) a=k-k^2+k^3-k^3ca=k-k^2+k^3/1+k^3=b=cbut a₦b₦cI. e. K^3=-1=>k=-w, -w^2
```
2 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions