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The equation of the parabola is of the formy2= 4ax(as it is opening to the right).
Since the parabola passes through point A (10, 5), 102= 4a(5)
100 = 20a
Therefore, the focus of the parabola is (a, 0) = (5, 0), which is the mid-point of the diameter.
Hence, the focus of the reflector is at the mid-point of the diameter.
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