Sher Mohammad
Last Activity: 10 Years ago
x^2 + y^2 + 2(a1)x +a1^2-a1^2+b = 0
center of first circle is (-a1,0) and radius is sqrt(a1^2-b)a1^2-2a1a2+b<0 (centre of first circle lies inside second circle)
a2^2-b>a1^2-b
a2^2>a1^2 >0 imply a2>a1>0 hence a1a2>0
and both radius a2^2>=b>0,a1^2>=b>0 imply b>0
a1^2-2a1a2+b<0
sher mohammad