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if a,b,c,d,e,f,g,h,i are 9 different natural numbers then how many 3x3 and 2x2 matrices are formed with these numbers?

if a,b,c,d,e,f,g,h,i are 9 different natural numbers then how many 3x3 and 2x2 matrices are formed with these numbers?
 
 

Grade:12

1 Answers

Ravi
askIITians Faculty 69 Points
7 years ago
A 3x3 matrix will have 9 vacant places for the numbers to be put in from the available options i.e. 9 given numbers. So Number of arrangements of 9 numbers at 9 different places = 9.8.7.6.5.4.3.2.1= 9!

Similarily for 2x2= 9.8.7.6
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