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Grade: 10 
        
If a²+b²+c²+d²=1
Then find the maximum value of
16abcd
11 months ago

Answers : (1)

Arun
15912 Points 
							
Dear Ishan
 
Maximum value occur when all of them are equal.
 
Hence
a²+a²+a²+a² = 1
a² = ¼
a = ½ = b = c = d
 
Hence
16*abcd = 16*(1/2)(1/2)(1/2)(1/2) = 16/16 = 1
 
Regards
Arun (askIITians forum expert)
11 months ago
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