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If a²+b²+c²+d²=1Then find the maximum value of16abcd
Dear Ishan Maximum value occur when all of them are equal. Hencea²+a²+a²+a² = 1a² = ¼a = ½ = b = c = d Hence16*abcd = 16*(1/2)(1/2)(1/2)(1/2) = 16/16 = 1 RegardsArun (askIITians forum expert)
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