If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

U can write it as (a^logb)(a^-logc)(b^logc)(b^-loga)(c^loga)(c^-logb) and now by rearranging it as (a^logb)(a^-logb).............. And the value equal to 1 But remember that u know the properties of logarithm