If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

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U can write it as (a^logb)(a^-logc)(b^logc)(b^-loga)(c^loga)(c^-logb) and now by rearranging it as (a^logb)(a^-logb).............. And the value equal to 1 But remember that u know the properties of logarithm

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If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

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If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

If a,b,c, are positive real numbers then a^logb-logc × b^logc-loga×c^loga-logb

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