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`        If a,b,c are non zero real numbers such that 3 (a2+b2+c2+1)=2 (a+b+c+ab+bc+ca), then a,b,c are in a) A.Pb)G.Pc)both a and bd) none of these    Pls give the solution  for this question[A2=a square and so on other two]   `
one year ago

```							 Dear student  a^2 + b^2 + c^2 + 1 = 2/3 a^2 + b^2 + c^2 = – 1/3 this can never happen as addition of some squares can never be negative hence a,b , c are not real numbers
```
one year ago
```							The above question is merely tricky.Note that the above equation can be written as (a-b)^2+(b-c)^2+(c-a)^2+(a-1)^2+(b-1)^2+(c-1)^2=0So a=b=c=1Hence a,b,c are in both AP and GP
```
one year ago
```							Oh sorry man I thought that the expression in second line is discrete.There is a silly mistake from my side in reading the question as expressions are written in diffrenet line
```
one year ago
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