if a b c are in gp and a^1/x=b^1/y=c^1/z prove that x y z are in ap
Aryan Todi
8 Years agoGrade 11
3 Answers
Arun
8 Years ago
z , c = ky, b = kxa = k k (let) =z = c1/y = b1/x1/a
now a,b,c are in g.p. (given)
hence b/a = c/b
ky / kx = kz / ky
k(2y) = k(x +z)
hence 2y = x + z
hence x, y, z will be in A.P.
Mohd Mujtaba
8 Years ago
Let a^1/x=b^1/y=c^1/z=m .soa=m^x,b=m^y, c=m^z. Now a b c are in gp so b^2=ac. This imply m^2y=m^z.m^x so comparing we get 2y=x+z. Hence a b c are in ap thank☺☺☺☺
Kushagra Madhukar
6 Years ago
Dear student,
Please find the attached solution to your question