If a+b+c=4 and (a^2+b^2+c^2 )=2 and x/a+y/b+z/c=√3 then xy+xz+yz=?

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Saurabh Koranglekar · Answer

Dear student The equations given are not sufficient to solve for all the variables, Please attach the question&rsquo;s image and repost Regards

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If a+b+c=4 and (a^2+b^2+c^2 )=2 and x/a+y/b+z/c=√3 then xy+xz+yz=?

If a+b+c=4 and (a^2+b^2+c^2 )=2 and x/a+y/b+z/c=√3 then xy+xz+yz=?

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If a+b+c=4 and (a^2+b^2+c^2 )=2 and x/a+y/b+z/c=√3 then xy+xz+yz=?

If a+b+c=4 and (a^2+b^2+c^2 )=2 and x/a+y/b+z/c=√3 then xy+xz+yz=?

1 Answers

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Other Related Questions on Algebra

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