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Grade: 9
        
if a+b+c= 3 and ab=2 then find value of (i)a^2+b^2 (ii) a-b
 
7 months ago

Answers : (1)

ankush rathee
36 Points
							(i) a^2+b^2=(a+b)^2-2ab                    =(3-c)^2-4                     =9+c^2-6c -4                    =c^2-6c+5                   = (c-1)(c-5)(ii) let (a-b) be X So (a-b)^2 =a^2+b^2-2ab=c^2-6c+5-4=c^2-6c+1So a-b= root (c^2-6c+1)
						
7 months ago
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