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If A+B+C = 180 then cos3A + cos3B + cos3C a. 1 - 4 sin3A/2sin3B/2sin3C/2 b. 4 cos3A/2cos3B/2cos3C/2 c. 1-4 cos3A/2cos3B/2cos3C/2 d. -4 cos3A/2cos3B/2cos3C/2

If A+B+C = 180  then cos3A + cos3B + cos3C

Grade:12

1 Answers

Shreshth graak
30 Points
5 years ago
Cos3A+cos3B+cos3C 
2[cos3(A+B)/2]cos3(A-B)/2 + cos3C
-2[sin3c/2]cos3(a-b)/2 + 1-sin²3c/2
1-2sin3c/2[cos3(a-b)/2 - sin3c/2
After solving this u git answer
 

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