Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
if a,b are roots of the quadratic equation 2 x 2 +6x+b=0 (b a/b+b/a is less than? A.2 B.-2
I guess B.As a nd b are roots of the equation, 2x2+6x+b=0, so we have two equatins:a+b = -(coeff of x)/(coeff of x2) = -3 …...(i)ab = (constant)/(coeff of x2) = b/2 …....(ii)So, from (ii) we have b(a-1/2)=0, as b cannot be zero (since root and putting x=0 we donot get LHS=RHS) so a-1/2=0 and thus a=1/2.Putting this value in (i) we get b = -3.5 Now, (a/b)+(b/a) = (a2+b2)/ab = [(a+b)2-2ab]/ab ….......(iii)Putting in values of (a+b) and ab we get (iii)= -7.14, less than -2.Cheers!!
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -