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If a,b are real, then the roots of the quadratic equation (a-b)x² - 5(a+b)x -2(a-b)=0 are :-

Real and equal.

Non-real complex.

Real nad unequal.

None of these.

Wilby Back

11 Years agoGrade Select Grade

1 Answer

Jitender Singh

Approved Tutor Answer11 Years ago

Ans:
Hello Student,
Please find answer to your question below

a, b are real.
$(a-b)x^2 - 5(a+b)x - 2(a-b) = 0$
Lets find out delta.
$\Delta = (-5(a+b))^{2}-4(a-b)(-2(a-b))$
$\Delta = 25(a+b)^{2}+8(a-b)^2$
(a+b)²and (a-b)²are always positive and greater than zero.
So their sum is also positive and greater than zero.
So discriminent is positive and greater than zero.
So roots are real and unequal.

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