If a,b and c are in geometric progression the line a^2 x +b^2 y + ac = 0 will always pass through 1) (0,1)2) (1,0)3) (0,-1)4) (1,-1)

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Arun · Answer

Dear Pratham it will always pass by (0, –1) because 0 – b^2 + ac = 0 b^2 = ac hence a,b, c are in G.P. option C is correct Regards Arun (askIITians forum expert)

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If a,b and c are in geometric progression the line a^2 x +b^2 y + ac = 0 will always pass through 1) (0,1)2) (1,0)3) (0,-1)4) (1,-1)

If a,b and c are in geometric progression the line a^2 x +b^2 y + ac = 0 will always pass through 1) (0,1)2) (1,0)3) (0,-1)4) (1,-1)

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If a,b and c are in geometric progression the line a^2 x +b^2 y + ac = 0 will always pass through 1) (0,1)2) (1,0)3) (0,-1)4) (1,-1)

If a,b and c are in geometric progression the line a^2 x +b^2 y + ac = 0 will always pass through 1) (0,1)2) (1,0)3) (0,-1)4) (1,-1)

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