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If a – b = 3 and b – c = 5, then the value of a2 + b2 + c2 – ab – bc – ca is ?
If a – b = 3 and b – c = 5, then the value ofa2 + b2 + c2 – ab – bc – ca is ?

```
3 years ago

Arun
25768 Points
```							A - b = 3 and b - c = 5 then a²+b²+c² - ab - bc - ca= ?a-b= 3⇒ a= 3+b ··· (1)b-c =5 ⇒ b= 5+c ···(2)From (1) and (2) we get, a = 3+5+c = 8+c •••(3)Now, a + b + c - ab - bc - ca = (8+c)²+(5+c)²+c² -(8+c)(5+c) - (5+c)(c) -(c)(8+c)=(64 + 16c +c²) + (25 + 10c + c²) + c² -(40+8c+5c+c²) - (5c+c²) - (8c+c²)=(64+25+ 26c + 3c²) - (40+26c+3c²)=(89 - 40)+ (26c -26c) + (3c² - 3c²)=89 - 40 =49
```
3 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions