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If a and b are non – real, then condition for x^2 + ax + b =0 to have real roots, is a)(a – ~a)(b – ~b) = (a~b – ~ab)^2 b) (a – ~a)(a~b – ~ab) = (b – ~b)^2 c)(b – ~b) (a~b – ~ab ) = (~a – a)^2 d)none of these

If a and b are non – real, then condition for x^2 + ax + b =0
to have real roots, is 
a)(a – ~a)(b – ~b) = (a~b – ~ab)^2
b)(a – ~a)(a~b – ~ab) = (b – ~b)^2
c)(b – ~b)(a~b – ~ab=(~a – a)^2
d)none of these

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1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

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