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if a 4 +1\a 4 =727,then the value of a 3 -1\a 3 is. How to solve it by using formulae

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4 years ago

```							a4+1\a4=727this the given eqn.Now add 2 both seds so that we can use the suitable identity.a^4 + 1/a^4 + 2 = 729(a^2)^2 + 1/(a^2)^2 + 2a^2/a^2 = 27^2(a^2 + 1/a^2)^2 = 27^2(a^2 + 1/a^2) = 27like this now sutract 2 both sides .R.H.D would become sq. of 5 that is 25.And u would get,a – 1/a = 5now then take cube both sidesand now substitute also (x – 1/x).
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4 years ago
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