If a 2 =b+c,b 2 =c+a,c 2 =a+b ,then find the value of 1÷(a+1)+1÷(b+1)+1÷(c+1)

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Arun · Answer

As if u solve the equation in 3 variable then u will get that a=2,b=2,c=2. and now if u put these values in 2nd equation then it will become 1/3+1/3+1/3=1

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If a 2 =b+c,b 2 =c+a,c 2 =a+b ,then find the value of 1÷(a+1)+1÷(b+1)+1÷(c+1)

If a²=b+c,b²=c+a,c²=a+b ,then find the value of
1÷(a+1)+1÷(b+1)+1÷(c+1)

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If a 2 =b+c,b 2 =c+a,c 2 =a+b ,then find the value of 1÷(a+1)+1÷(b+1)+1÷(c+1)

If a2=b+c,b2=c+a,c2=a+b ,then find the value of 1÷(a+1)+1÷(b+1)+1÷(c+1)

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If a²=b+c,b²=c+a,c²=a+b ,then find the value of
1÷(a+1)+1÷(b+1)+1÷(c+1)