if a²=b+c ; b²=a+c ; c²=b+a then find the value of 1/(a+1)+1/(b+1)+1/(c+1)

a^2=b+c then a=(b+c)/a; similarly b=(c+a)/b and c=(a+b)/cOn Putting these values in1/(a+1)+1/(b+1)+1/(c+1)=1/[{(b+c)/a}+1]+1/[{(c+a)/b}+1]+1/[{(a+b)/c}+1] on simplifyinga/(a+b+c)+b/(a+b+c)+c/(a+b+c)=(a+b+c)/(a+b+c)=1