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If a 2 , b 2 and c 2 are in A.P., then prove that b+c, c+a, a+b are in H.P.
If a2, b2 and c2 are in A.Pb2 -a2 = c2-b2 (b-a)(b+a)=(c-b)(c+b)(b-a)/(c+b)=(c-b)/(b+a)(b-a+c-c)/(b+c)=(c-b+a-a)/(a+b)(b-a+c-c)/(b+c)(c+a)=(c-b+a-a)/(a+b)(c+a){1/(c+a)} − {1/(b+c)} = {1/(a+b)} - {1/(c+a)}1/(b+c),1/(c+a),1/(a+b) are in A.P.So b+c, c+a, a+b are in H.P.
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