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if 5x +2y=14 and x,y>0 then the maximum value of x^3y^4 is

KAUSHIK SUBRAHMANIAN , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Z = x^3.y^4 
substiitute  y from eqn. 5x +2y=14 in Z
and then differentiagte it w.r.t x and equate it to zero.
Reject negative values of x and substitute in Z for maximum value.

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