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if 3s=a+b+c, then (s-a)^2/(s-b)(s-c)+(s-b)^2/(s-a)(s-c)+(s-c)^2/(s-a)(s-b)=?

 if 3s=a+b+c, then (s-a)^2/(s-b)(s-c)+(s-b)^2/(s-a)(s-c)+(s-c)^2/(s-a)(s-b)=?

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
When we take LCM
 
We get
(s-a)³ + (s-b)³ + (s-c)³ /(s-a)(s-b)(s-c)
 
Since 3s = a + b+c
 
Then
 
Denominator will become
 
3 (s-a)(s-b)(s-c). Hence answer will be 3
 

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