Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
if 30,72 and x are three integers, such that the product of any two of them is divisible by the third ,then the least value of x is...?

```
2 years ago

```							30, 72, and XThere must exist positive integers A, B, and C such that 30·72 = XA  30X = 72B  72X = 30CSimplifying:2160 =  XA  5 = 12B 12X =  5C  Solving each for X:X = 2160 /AX = 12 B/ 5X = 5 C /12Set the last two right sides equal, since both are equal to X12 *B/ 5 = 5 * C / 12144B = 25CThe smallest B and C can be are B = 25 and C = 144Substituting inX = 12B/ 5 = 12*25/ 5 = 60 X = 5C / 12 = 5 * 144/ 12 = 60That works because30, 72, and 6030*72 = 2160 = 60*3630*60 = 1800 = 73*2560*72 = 4320 = 30*144So the answer is X = 60​
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions